Question

Please help.
What are the solutions to the following system of equations?
y = x2 + 12x + 30
8x − y = 10

(−4, −2) and (2, 5)

(−2, −4) and (2, 5)

(−2, −4) and (5, 2)

No Real Solutions

Answer 1

the second equation is the same as
\[y=8x-10\] plug it in to the top one and you can solve \[8x-10=x^2+12x+30\]

Answer 2

I got \[x ^{2}+4x+40\]

Answer 3

No Real Solution!!!!!

Answer 4

set it equal to zero via
\[x^2+4x+40=0\]

Answer 5

yeah like that

Answer 6

subtract 36 from both sides, and complete the square.

Answer 7

and then @Agl202 tell you that there is no real solution, which is true

Answer 8

sorry

Answer 9

you were right, alg.

Answer 10

thx....

Answer 11

I was going to say, that from where satelline left off, if you subtract 36 from both sides, and complete the square (as i said before), you will then end up with imaginary solutions.