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Mathematics 14 Online
OpenStudy (anonymous):

If $396 is invested at an interest rate of 13% per year and is compounded continuously, how much will the investment be worth in 3 years?

OpenStudy (agl202):

584.88

OpenStudy (anonymous):

Use the compounded continuously formula. \[A = Pe ^{rt}\] P is 396, e is a constant, r is your interest RATE, and t is time, 3 years.

OpenStudy (anonymous):

@Agl202 how did you solve it?

OpenStudy (anonymous):

@Agl202 actually you did someone else's math

OpenStudy (anonymous):

@Kommander_Kitten what did you plug in for the variable e?

OpenStudy (anonymous):

I used the compounded continuously formula and I got to A=$396e^(.39) but I don't know what to do next...

OpenStudy (anonymous):

e is not a variable. 'e' is a mathematical constant, also known as Euler's number. It is the base of the natural log. It's approximately 2.71828. It should be a button on your calculator.

OpenStudy (anonymous):

A is your final answer. Just plug it into your calculator.

OpenStudy (anonymous):

thank you @Kommander_Kitten

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