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Mathematics 23 Online
OpenStudy (anonymous):

Help?!?! This is soo confusing!! When you are graphing an inequality how do you know which part of the graph to shade in? And how do you determine if the line is solid or dotted?

jimthompson5910 (jim_thompson5910):

Let's say we want to graph y < 3x+5

jimthompson5910 (jim_thompson5910):

the "less than" sign means we shade below the boundary line the boundary line itself is dotted/dashed because we are NOT including the boundary

jimthompson5910 (jim_thompson5910):

if we flip the "less than" sign to a "greater than" sign, then we shade above the boundary line the boundary line is only solid if you have "or equal to" attached to the inequality sign

jimthompson5910 (jim_thompson5910):

oh and I nearly forgot, but the boundary line is simply the graph of y = 3x+5 (in this example)

OpenStudy (anonymous):

Ok so if the inequality sign had a line under it meaning less than or equal to you would have a solid line

jimthompson5910 (jim_thompson5910):

correct because that means to include the boundary in the solution set

jimthompson5910 (jim_thompson5910):

this only works if y is completely isolated

OpenStudy (anonymous):

Okay so what if you have like x+3y<4 or something? and y isnt by itself

jimthompson5910 (jim_thompson5910):

we have to solve for y first x+3y<4 3y<4-x 3y < -x + 4 y < (-1/3)x + 4/3

jimthompson5910 (jim_thompson5910):

in this case, the inequality sign didn't flip, but it will flip when you divide both sides by a negative number example: -2y > 5 turns into y < -5/2

OpenStudy (anonymous):

Ohh okay so you would have to solve for y first that graph..makes sense And the sign ONLY flips for negative numbers?

OpenStudy (anonymous):

then*

jimthompson5910 (jim_thompson5910):

yes when you multiply or divide both sides by a negative number

OpenStudy (anonymous):

Ok thank you soo much!

jimthompson5910 (jim_thompson5910):

you're welcome

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