Question

HE lp !! !!

Find the 9th term of the sequence described by: A(n) = 7 + (n-1)(3)

A) 42
B) 9
C) 31
D) 27

Answer 1

where you see an \(n\) put a \(9\)
compute
\[A_9=7+(9-1)\times 3\] that is all

Answer 2

Do u mean A^9 ?

Answer 3

a(9)=7+24=31

Answer 4

so the 9th term is 31

Answer 5

so C ?

Answer 6

at the risk of repeating myself, replace \(n\) by \(9\)!

Answer 7

\[A_9=7+(9-1)\times 3\] see what you get when you do that piece of arithmetic

Answer 8

yeah but do u mean A^9

Answer 9

does it say \(A^9\) ?

Answer 10

no but i don't know how to do the other one

Answer 11

i wish i knew another way to put it
you want \(A_{\color{red}9}\) and you have \[A_\color{red}n=7+(\color{red}n-1)\times 3\]
therefore
\[\huge A_{\color{red}9}=7+(\color{red}9-1)\times 3\]

Answer 12

does A 9 mean Ax9 ?

Answer 13

Dan, help me out here

Answer 14

no it means the ninth term

Answer 15

the first term is \(A_1\) the second is \(A_2\) the third is \(A_3\) and the nth is \(A_n\)
you want the ninth term

Answer 16

C ?

Answer 17

31 ?

Answer 18

yes

Answer 19

THX !

Answer 20

yw