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PLEASE HELP!! MEDAL!!
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?what u need help
\[\frac{ 1 }{ 7(x-3) } +\frac{ 4 }{ 7 } =\frac{ 3 }{ (x-3) }\]
@torifamelol
What do you have to do exactly... I see you added etc. But what do you need help with? the x-3? If so what's needed to solve for it.
solve for it? lets go slow
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the common denominator for \[\frac{ 1 }{ 7(x-3) } +\frac{ 4 }{ 7 } =\frac{ 3 }{ (x-3) }\] is \(7(x-3)\)
write each fraction so that the denominator for each is \(7(x-3)\)
or better yet multiply both sides of the equation by \(7(x-3)\) to get rid of the denominators all together
in one step, cancelling as you go, you get \[1+4(x-3)=3\times 7\] and that is easy enough to solve
|dw:1422583815278:dw|
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