Question

C++ help please.
x = 1;

if int y = (++x)++ how do I evaluate this?

Answer 1

```
int y = (++x)++
```
gets interpreted as
```
int y = (++x);
x++;
```
which in turn is processed in the following order:

```
(++x); //x->2
int y = x; //y=2
x++; //x=3
```

Answer 2

Because of the "if" there, it will return true if the assignment happens. So as long as x exists and can use the ++ incrementors, then y will be assigned and therefore return true as a result and the if will succeed. But if x does not exist, then the assignment will fail and it will be false.

Answer 3

As written, it will evaluate as a syntax error, it won't compile. if requires parenthesis in C derived languages.

if( y = (++x)++ )

Then e.mccormick is right, and it happens like bibby explained.

Answer 4

Ah, true. I missed the ( ) requirment. The joy of tricky questions...