Can someone please help me? ^_^ This is the problem: http://gyazo.com/6f9e587eb674af5a4107da1d76fefe18
I have no idea how to start it, if someone could kindly step me through it, that'd be awesome as well .
@jordanloveangel
m i try but no promises
Alright, thank you regardless.
i think its C but not sure
If you don't mind, can I know how you worked it out? cause there is another problem like this one.
its pretty hard tbh just try 2 cope it and sreach it on google
Tried that, couldn't really find much that was helpful lol.
oh
@Directrix Do you think you could help? ^_^
Yes. Just a sec.
Thnank you very much. I answered the last question btw. So I went ahead and closed it :). Thank you also for that one.
If the two triangles in the diagram are similar, then it would have to be true that the smallest side of the first triangle over the smallest side of the second triangle would have to be equal to the middle side of the first triangle over the middle side of the second triangle. Then, the same for the largest side of the first triangle over the largest side of the second triangle.
The question comes to this: Is this extended proportion true: 3/4 = 5/6 = 6/8 Is that true?
Hrm, I am not sure to honest. I am horrible with proportions and fractions :/.
Get a calculator or use the Google calculator and see what the decimal equivalents are for each of the fractions.
Ok, one second please.
1.3, 1.2, and 1.3
So they are not similar?
3/4 = .75. I think you did 4/3 but if you were systematic and divided the all that way, then that is sufficient to show that the triangles are NOT similar.
Oh I was dividing by the biggest to the smallest.
>>So they are not similar? Correct, not similar
Thank you, :D. If you don't mind could I borrow your knowledge for 2 more questions?
What was the brainly.com answer for that? I should go over and correct it.
It was like 15.8 or something. Let me double check it.
>>>If you don't mind could I borrow your knowledge for 2 more questions? I will try to help if you post each question in separate, new threads.
Oh nvm, the brain comment was for a different question I had. I got the two mixed up.
and I will, I will close this one ^_^, thanks again. I will tag you once I post the new thread?
Yes.
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