How can I prove that this converges?
\[\int\limits_{0}^{\frac{ \pi }{ 2 }}\tan ^{2}(2x)dx\] Edit: It doesn't converge, it diverge.
I seperated into 0 to pi/4 and to pi/4 to pi/2 because the "blow-up" point is at pi/4
\[\int\limits_{0}^{\frac{ \pi }{ 4 }}+\int\limits_{ \frac{ \pi }{ 4 }}^{\frac{ \pi }{ 2 }}\] it goes to + infinity but do I just write that? Is there anything else I could calculate to prove it. limit comparison or something?
Please note that you have to calculate these quantities: \[\lim _{\sigma \rightarrow \pi/4-}\int\limits_{0}^{\sigma} [\tan(2x)]^{2}dx\] and: \[\lim _{\delta \rightarrow \pi/4+}\int\limits\limits_{\delta}^{\pi/2} [\tan(2x)]^{2}dx \]
furthermore, keep in mind that: \[\int\limits [\tan (2x)]^{2}dx=\frac{ \tan(2x)-(2x) }{ 2 }+c\] where c is a real arbitrary constant
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