Question

Need help for medals:

http://gyazo.com/1a9687f7d4c3dbb449e22d86c99a69eb

Answer 1

@Directrix

Answer 2

Compare the posted equation to that of the attached standard equation. Pick out the center and radius.

Answer 3

please compare your formula with this one:
\[(x-a)^{2}+(y-b)^{2}=r ^{2}\]
which is the equation of a circumference whose center is the point (a,b) and whose radius is r

Answer 4

I am completely lost on this one, sorry :/.

Answer 5

I re-write your equation as below:
\[\left( x-\frac{ 5 }{ 2 } \right)^{2}+\left( y-\left( \frac{ 27 }{ 5 } \right) \right)^{2}=\frac{ 11 }{ 100 }\]
what are a, b and r?

Answer 6

oops... I have made an error of sign, I re-write your equation:
\[\left( x-\frac{ 5 }{ 2 } \right)^{2}+\left( y-\left( -\frac{ 27 }{ 5 } \right) \right)^{2}=\frac{ 121 }{ 100 }\]

Answer 7

Doesn't it just go in order? 1:a , 2:b, and 3:r?

Answer 8

please you have to compare both equations, fr example, we have:
\[a=\frac{ 5 }{ 2 }\]

Answer 9

Yeah that's what I meant. a= 5/2 and b = -27/5 and r = 121/100

Answer 10

wait please we have:
\[r=\frac{ 11 }{ 10 }\]
since it is:
\[r ^{2}=\frac{ 121 }{ 100 }\]

Answer 11

Ah, ok, sorry.

Answer 12

So the answer is C, correct?

Answer 13

@Directrix

Answer 14

@Judach Would you type in your equation? (LaTex free, please)