Solve 2(x+3)^2 -4 =6
the answer is x= -3 +- square root of 5
Just need to show the work and idk how.
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jagr2713 (jagr2713):
correct :D
jagr2713 (jagr2713):
ok now we are going to work on this :D
jagr2713 (jagr2713):
since -4 does not contain the variable to solve for, move it to the right side of the equation by adding 4 to both sides
2(x+3)^2=4+6
jagr2713 (jagr2713):
add 4 and 6 to get 10
2(x+3)^2=10
jagr2713 (jagr2713):
what do you think we do next @SPHott51
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OpenStudy (radar):
Divide thru by 2 getting (x+3)^2 -2 = 3 now add 2 to both sides; That gives you (x+3)^2 = 5 Now take the sqrt of both sides. Giving: x + 3 = sqrt 5 Now solve for x getting you what you expected.
jagr2713 (jagr2713):
@SPHott51 you there
OpenStudy (sphott51):
Yeah, I'm here
jagr2713 (jagr2713):
do you know what we do next :D
OpenStudy (sphott51):
a few.. Just dont know to to solve x-3= sqrt 5 to get the x..
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jagr2713 (jagr2713):
well next we divide each term in the equation by 2
2(x+3)^2/2=10/2