Statistics question about probability based on combination formula. Please see attached photo for question. part a, i tried => ( 25C6 * 12C0) / 36C6 part b, i did 1-ans for part a. Please assist
what do you have so far
there are 25 out of 37 cells capable of replication, so there is a 25/37 probability of capable of replication
part a) \[\frac{ 25C6 * 12C0 }{ 37C6 } = 0.0761\]
probability of choosing 6 cells capable of replication. Since we have without replacement, it should be (25/37)*(24/36)*(23/35)*(22/34)*(21/33)
That is the probability of probability (first cell replicates & second cell replicates & third cell & fourth cell & fifth cell & sixth cell)
Oh ok, is it similar to an at least question?
we are using P( A & B ) = P( A ) * P ( B | A )
the at least is a little different
it is easier if you approach it using complement method
P ( at least one is not capable of replication) = 1 - P ( all are capable of replication)
Ok, thanks a lot.
Join our real-time social learning platform and learn together with your friends!