solve (x) / (x-4) - (1) / (x+3) = (28) / (x^2 -x -12)
the answer is {-6}
needs to show the work and idk how to get there

Question

solve (x) / (x-4) - (1) / (x+3) = (28) / (x^2 -x  -12) 
the answer is {-6} 
needs to show the work and idk how to get there

anonymous · Answer

$$\frac{x }{ (x-4) } - \frac{ 1 }{ (x+3) } = \frac{ 28 }{ (x^2-x-12) }$$ is this your problem

anonymous · Answer

For the left side find a common denominator, remember when doing fractions $$\frac{ a }{ b } \pm \frac{ c }{ d } = \frac{ ad \pm bc }{ bd }$$

anonymous · Answer

What do you get when you factor $$(x^2-x-12)$$

anonymous · Answer

Hey are you there?

sphott51 · Answer

Yeah, sorry, Wasn't on

sphott51 · Answer

I got (x+4) (x-3)

mathstudent55 · Answer

Close, but it's $(x - 4)(x + 3) $

sphott51 · Answer

Okay, I got it corrected now

mathstudent55 · Answer

That means you have now:

$\dfrac{x}{x - 4} - \dfrac{1}{x + 3} = \dfrac{28}{(x - 4)(x + 3)}$

Ok?

mathstudent55 · Answer

Now you need to subtract the fractions on the left side.
Use the common denominator (x - 4)(x + 3) to do the subtraction.

sphott51 · Answer

I subtract both numerator and denominator with (x-4)(x+3) ?

mathstudent55 · Answer

When you subtract fractions with a common denominator, you use the same denominator and subtract the numerators.

mathstudent55 · Answer

First, you need to multiply each fraction to get the common denominator.

sphott51 · Answer

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