Question

one number is 7 more than twice the other number.If the sum of the two numbers is 37, find the numbers ! Please help in need !!

Answer 1

let x and y be the two numbers

Answer 2

"one number is 7 more than twice the other number"

so that means

y = 2x+7

Answer 3

"the sum of the two numbers is 37"

meaning that

x+y = 37

Answer 4

so the first equation is 2x+7 ??

Answer 5

y = 2x+7

you need the equal sign to have it be an equation

Answer 6

x+y = 37

x+2x+7 = 37 ... replace y with 2x+7 (works because y = 2x+7)

3x+7 = 37

x = ???

Answer 7

i have 2x^2 +7x-37=0 but that doesnt factor

Answer 8

x=3

Answer 9

that's incorrect

Answer 10

x = 3 is correct though

Answer 11

3x+7 = 37 leads to x = 3

Answer 12

if x = 3, then y = 2x+7 = ???

Answer 13

so the other # is 13?

Answer 14

yes

Answer 15

thank you!

Answer 16

actually hold on

Answer 17

sorry I jumped the gun

Answer 18

3x+7 = 37 leads to x = 10 and NOT x = 3

Answer 19

you should have 3x = 30 ---> x = 10

Answer 20

if x = 10, then y = 2x+7 = 2(10)+7 = 27

Answer 21

okay so 10 and 27

Answer 22

thank you !

Answer 23

yes and you check by adding them: 10+27 = 37