Question

how much of a (n)80% orange juice drink must be mixed with 3 gallons of a 30% orange juice mix to obtain a mixture that is 50% orange juice

Answer 1

anybody i really need help answering this question @Data_LG2

Answer 2

we need a variable

Answer 3

say \(x\) is the amount of 80% orange juice, which will have \(.8x\) orange juice
then add it to 3 gallons of 30% juice which will have \(30\times .3=9\) gallons of juice

Answer 4

the total will be \(x+50\) gallons which you want to be 50% juice set
\[.8x+9=.5(x+50)\] and solve for \(x\)

Answer 5

x=53.3

Answer 6

yah but i made a mistake

Answer 7

should be\[.8x+9=.5(x+3)\]

Answer 8

x=-25

Answer 9

man i am all messed up hold on

Answer 10

okay !

Answer 11

not 30 gallons, 3 gallons!!

Answer 12

haha yes 3 !

Answer 13

\[.8x+.9=.5(x+3)\]

Answer 14

so \(x=2\)

Answer 15

okay so the answer to the question is 2

Answer 16

yes

Answer 17

thank you ! i

Answer 18

i have another question if you could help me