Question

A sample containing only CaCO3 and MgCO3 is ignited to CaO and MgO. The mixture of oxides weighs exactly half as much as the original sample. Calculate the % CaCO3 and MgCO3 in the sample.

Guys need some help with this problem! :(

Answer 1

\(\huge\color{Green}{{\rm welcome}\rm~to~open~study!!!!}\)\(\Huge \color{orange}{\star^{ \star^{\star:)}}}\Huge \color{purple}{\star^{ \star^{\star:)}}}\)
this is math section
if you look at the top there is "find more subject" click on it and find correct section for that question

Answer 2

I'll use approximate values for the problem, say
molar mass for CaCO3 = 100
molar mass for MgCO3= 60
molar mass for CaO = 56
molar mass for MgO = 40
Say 10 g of CaCO3 was used, and X g of MgCO3 was used, then

Say we started with 100 g of CaCO3 and X g of MgCO3
Mass before heat: 100+X
mass after heat: 56+(40/60)X
set up equation, knowing that the total mass after heating is half the original.
100+X = 2 ( 56+ (40/60)X )
from which you can solve for X and hence the ratio.

NOTE:
As @Nnesha mentioned, look for the chemistry section to make your post. If there is no answer, then you can go to whichever section to solicit help, with reference to your post. It is against the rules to post (and answer) question in the irrelevant section.

Answer 3

Thank you matchmate and I'm sorry! Its just that this is my first time joining in some open study so I dont know the rules. Sorry.

Answer 4

yeah i know ur new that's why i told about it :) :)
don't have to say sorry
:)

Answer 5

Yeah. Thanks anyway! :)

Answer 6

np and do you know you can give medal ot that person who helped u ??

Answer 7

Nope. How can I gave medal to that person?

Answer 8

if you got the help then you can close this question
click here to close

Answer 9

@hayame03
Please note that in my example, the molar mass of MgCO3 was inadvertently assigned as 60 instead of the closer approximation of 84. But the principle is the same.