What are the x-coordinates of the solutions to this system of equations A. -4 and 0 B. 4 and 0 C. -3 and -5 D. 3 and -5
X^2+y^2=25 Y=2x-5
Ok, @phi may be able to help you on this
Ok thanks!
No problem! Welcome to OpenStudy!
Thanks!
you can solve the system, or you can test the choices. to test choice A (for example) start with x=-4 and use the second equation to find y can you do that ?
I'm not sure what to do
At allll
start with y=2x-5 if x= -4 , what is y ? do find out , erase the "x", and put in -4 (remember 2x means 2 times x) can you do that ?
Y=-13 ?
Y=0
y=2x-5 with x=-4, we get y= 2* (-4) -5 y= -8 -5 (order of operations means we do multiply first) y= -13 this mean when x=-4 y= -13 now we test if this pair works in the first equation (which is a circle by the way) (-4)^2 + (-13)^2 = 25 I don't need a calculator to know that -13*-13 is bigger than 100 (because 10*10 is 100) and -4*-4 is 16. we will not get 25. all of that means x=-4 is not part of the answer. so choice A is not the answer
now let's test choice B let x=4 and find y, using y=2x-5 can you find y ?
replace the x with 4 in y=2x-5 and simplify
Y=3
ok. so for choice B, we have x=4, y=3 can you use those numbers in the first equation \[ x^2 + y^2 = 15 \] ?
No 16+9 =15 it doesn't work
oh, I typed in the first equation wrong.
can you use the correct equation and try again ?
X^2+y^2=25
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