Question

I am currently stuck on an electrical potential energy problem in physics. I would appreciate any help you could provide me with this problem. The problem is attached in the link below. Thank you.

Answer 1

Where is this link :P

Answer 2

@Catch.me

Answer 3

V= k*q/r.
r is constant and this is a scalar quantity so just add charges for each diagram and compare their resultant

Answer 4

I have already attempted this method and still got the wrong answer.

Answer 5

tell your answer depending on this method

Answer 6

a>b>d>c

Answer 7

HOW!!

Answer 8

I had a friend help who got the same answer. What did you get as an answer?

Answer 9

I will do it for two figures and you complete the rest.
V(figure a)=-7q*k/r
V(figure d)=- 7q*k/r

Answer 10

I found out c but i am still struggling with b

Answer 11

@Catch.me

Answer 12

c=1

Answer 13

how c = 1 !!
use the rule

Answer 14

@Catch.me I am using the rule obviously not correctly. If you could show your work for your answers rather than just stating your answers that could be of help.

Answer 15

I told you the rule is kq/r for each one isolated and v is scalar so the net is simply by adding them algebraically.
I will do figure a in details this time:

V at O from the upper charge=
\[V _{0Up}=\frac{ 2qk }{ r }\]
V at O from the right=
\[V _{OR}=\frac{ -9qk }{ r }\]
V total= their sum=
\[V _{t}= \frac{ 2qk }{ r }-\frac{ 9qk }{ r }= \frac{ -7qk }{ r }\]

Answer 16

@c_c_mill