Question

Check my work?
A right triangle is formed by the x-axis, the y-axis, and the line y=(-2x)+5. Find the length of the hypotenuse. It didn't give a picture but I'm going to post a picture of a graph i made in a comment. The answer I got was the square root of 50.

Answer 1

did you find the x- and y- intercept of that line?

Answer 2

find the x and y intercepts and calculate teh distance from two points \(d = \sqrt{(x1-x0)^2 + (y1-y0)^2}\)

Answer 3

i got 5.6

Answer 4

here \((x1,y1)\) and \((x0,y0)\) are the x and y intercepts

Answer 5

The y-intercept I got was 5 because that was given in the equation, and the x-intercept i got was(5/2) when I plugged 0 in as y. I did what @M4thM1nd said and thats how i got the square root of

Answer 6

1) set y=0 and isolate for x (x=5/2)
2) set x=0 and isolate for y (y=5)
3) now you have 2 side lengths so use a^2 + b^2 = c^2 to find c which is hypoteneuse
4) c^2 = (5)^2 + (5/2)^2
5) c = 5.6

Answer 7

so you have \(d = \sqrt{(2.5-0)^2 + (5-0)^2} \approx 5.59\)

Answer 8

Okay, thank both of you guys for the help! I feel bad because I can only award best answer once