Question

Simplify.7 square root of 3 end root minus 4 square root of 6 end root plus square root of 48 end root minus square root of 54

11 square root of 6 end root minus 7 square root of 12
11 square root of 3 end root minus 7 square root of 6
negative 3 square root of 9
4 square root of 9

Answer 1

@lizz123

Answer 2

You can only add roots that have the same number inside. So start by simplifying the bigger roots (sqrt48 and sqrt54).

Answer 3

ok

Answer 4

What did you get when you simplified?

Answer 5

idk @jwhite12 i believe the answer is c o. d

Answer 6

\[\sqrt{48}=\sqrt{16}\sqrt{3}=4\sqrt{3}\]
\[\sqrt{54}=\sqrt{9}\sqrt{6}=3\sqrt{6}\]

So then the problem is:
\[7\sqrt{3} - 4\sqrt{6} + 4\sqrt{3} - 3\sqrt{6}\]

Add or subtract the outside numbers of the like radicals.

Answer 7

@SolomonZelman @sleepyjess

Answer 8

Just do what @jwhite12 is telling you.

Answer 9

idk how to do that @sleepyjess

Answer 10

\(7\sqrt3 + 4\sqrt3\)

Answer 11

what is 7+4

Answer 12

11 @sleepyjess

Answer 13

the answer is b @sleepyjess

Answer 14

Ok, but do you understand?

Answer 15

yes @sleepyjess

Answer 16

Which statement is true about the product square root of 2(3square root of 2 + square root of 14)?

It is rational and equal to 12.
It is rational and equal to 18.
It is irrational and equal to 6 + 2square root of 18.
It is irrational and equal to 3 +square root of 18.

Answer 17

@sleepyjess

Answer 18

I think that @jwhite12 is better at this than I am

Answer 19

i think he is asleep or not paying attention to us tbh

Answer 20

Can you type the question in the equation editor?

Answer 21

^^^^^^ that would also make it easier to help

Answer 22

um sure

Answer 23

\[\sqrt{2}(\sqrt[3]{2} +\sqrt{18}\]

Answer 24

is that better??? @sleepyjess @jwhite12

Answer 25

Is it \[3\sqrt{2}\]
or \[\sqrt[3]{2}\]

Answer 26

Start by simplifying the \[\sqrt{18}\]
Do you know how to do that?

Answer 27

2nd one and no

Answer 28

@jwhite12 @sleepyjess

Answer 29

You have to break 18 into factors where one is a perfect square. So 18 breaks into 9 and 2. Then you square root the 9 to get 3, and that's your new outside number, keeping the 2 inside.
So...

Answer 30

\[\sqrt{18}=\sqrt{9}\sqrt{2}=3\sqrt{2}\]

Answer 31

ok

Answer 32

so d @jwhite12

Answer 33

Are you sure it's not written as \[3\sqrt{2}\] in the original problem?

Answer 34

yes

Answer 35

I think that 3 is supposed to be in front of the radical, not the index. I know it looks a little higher, but it may be the equation editor your teacher is using. If it were the index if would be inside the radical (check mark thing). And that's not the type of question you've been having anyway. AND if the index is 3, then none of those answers are right. So I'm going to assume it's outside...

Answer 36

ok

Answer 37

That gives us:
\[\sqrt{2}(3\sqrt{2}+3\sqrt{2})\]
We have "like radicals" inside the parentheses, so we can add the outside numbers...

Answer 38

Then we have
\[\sqrt{2}(6\sqrt{2})\]

Answer 39

We can multiply the numbers inside the radical and keep the 6 outside, so we get
\[6\sqrt{4}\]

Answer 40

ok

Answer 41

Do you know what that simplifies to?

Answer 42

no

Answer 43

Do you know the square root of 4?

Answer 44

2

Answer 45

Good, so that problem becomes 6 times 2.

Answer 46

12

Answer 47

That's it!

Answer 48

thank you d oyou mind checking if my answer are correct for my other questions

Answer 49

sure

Answer 50

Simplify. square root of 5 open parentheses 10 minus 4 square root of 2 close parentheses

14
15 square root of 2
5 square root of 2 end root minus 4 square root of 10
None of the above

Answer 51

d?

Answer 52

@jwhite12

Answer 53

Is it
\[\sqrt{5}(10-4\sqrt{2})\]
?

Answer 54

yes @jwhite12

Answer 55

please just tell me is it correct

Answer 56

yes it's d