Question

The sum of three consecutive integers is 33. Find the integers

Answer 1

Show work

Answer 2

x+(x+1)+(x+2)=33
3x+3=33
Subtract both sides by 3
3x+3-3=33-3
3x=30
Divide both side by 3
3x/3=30/3
x=10

Answer 3

Welcome to OpenStudy :D
You may want to read the code of conduct ( http://openstudy.com/code-of-conduct ).
Don't forget to click on the button called "Best Answer" to give a medal to the person who helped you :)

Answer 4

Wait isn't there more to the answer?

Answer 5

it's 10,11 and 12 @sabby75488 :)

Answer 6

3 consecutive integers are 10,11 and 12

Answer 7

x=10
put value in this equation
x+(x+1)+(x+2)=33
10+11+12=33
33=33

Answer 8

whose sum is 33. :)

Answer 9

Okay can we show work idk how you got 10,11, and 12?

Answer 10

@Nurali had show u the working. :)

Answer 11

x=10 answer value
x+1=10+1=11
x+2=10+2=12

Answer 12

\[x+(x+1)+(x+2)=33\]\[x+x+1+x+2=33\]\[3x+3=33\]\[3x=33-3\]\[3x=30\]\[x=10\]substitute x=10 in the equation \[x+(x+1)+(x+2)=33\]\[(10)+(10+1)+(10+2)=33\]\[10+11+12=33\]Therefore the 3 consecutive integers are 10,11 and 12 whose sum is 33. @sabby75488