Ask your own question, for FREE!
Chemistry 8 Online
OpenStudy (toxicsugar22):

convert each H30+ Concentration to a pH value a. 3.4 *10^-3 M b. 4.37 *10^-13 M

OpenStudy (toxicsugar22):

@Data_LG2

OpenStudy (toxicsugar22):

now how would i do this

OpenStudy (anonymous):

From the steps that I told you before, only do step 1 :)

OpenStudy (anonymous):

\(\sf pH=-log[H^+]\)

OpenStudy (toxicsugar22):

ok

OpenStudy (toxicsugar22):

so -log( 3.4* 10^-3)

OpenStudy (toxicsugar22):

would that be how to set it up

OpenStudy (anonymous):

yes

OpenStudy (toxicsugar22):

it is 2.468521083

OpenStudy (toxicsugar22):

right

OpenStudy (anonymous):

yes :)

OpenStudy (toxicsugar22):

thanks

OpenStudy (anonymous):

how about the 2nd one? you get it?

OpenStudy (toxicsugar22):

yes i got it

OpenStudy (toxicsugar22):

what about this one. calculate the H30 + concentration from the pH 1.90

OpenStudy (toxicsugar22):

how would i do this

OpenStudy (anonymous):

so from [H+] to pH is : \(\sf [H+]= 10^{-pH}\), replace pH with 1.90

OpenStudy (toxicsugar22):

.01258

OpenStudy (anonymous):

yep!

OpenStudy (toxicsugar22):

so is this the anwer

OpenStudy (toxicsugar22):

but is wants ________*10^M

OpenStudy (anonymous):

then change it to scientific notation, 0.01258 is same as \(\sf 1.258\ x\ 10^{-2} M\)

OpenStudy (toxicsugar22):

THANKS

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!