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convert each H30+ Concentration to a pH value a. 3.4 *10^-3 M b. 4.37 *10^-13 M
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@Data_LG2
now how would i do this
From the steps that I told you before, only do step 1 :)
\(\sf pH=-log[H^+]\)
ok
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so -log( 3.4* 10^-3)
would that be how to set it up
yes
it is 2.468521083
right
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yes :)
thanks
how about the 2nd one? you get it?
yes i got it
what about this one. calculate the H30 + concentration from the pH 1.90
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how would i do this
so from [H+] to pH is : \(\sf [H+]= 10^{-pH}\), replace pH with 1.90
.01258
yep!
so is this the anwer
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but is wants ________*10^M
then change it to scientific notation, 0.01258 is same as \(\sf 1.258\ x\ 10^{-2} M\)
THANKS
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