Question

help please

Answer 1

depends on what kind of question but i can help

Answer 2

sec

Answer 3

\[\frac{ (x +y)xy}{3xy }=\frac{ x +y}{3}\]

Answer 4

can you explain how the first expression simplifies to the second.

Answer 5

@danjs

Answer 6

well in the numerator there is xy which cancels out the xy in the denominator

Answer 7

true, but isn't the value of x and y = 1?

Answer 8

its not necessarily one it can be any number

Answer 9

x*x = x^2 right?

Answer 10

yes x *x does equal x^2 but if you divide x^2 by x it would equal x

Answer 11

\[\frac{ xy }{ xy } = \frac{ 1 }{ 1 }\]

Answer 12

\[\frac{ (x+y) }{ 3 }*\frac{ xy }{ xy } = \frac{ (x+y) }{ 3 }*\frac{ 1 }{ 1 } = \frac{ (x+y) }{ 3 }\]

Answer 13

you could look at it like this , using exponent rules
\[\frac{ xy }{ xy } = x^1*x^{-1}*y^1*y^{-1} = x^{1-1}*y^{1-1}\]

Answer 14

\(\bf \cfrac{ (x +y)\cancel{ xy}}{3\cancel{ xy} }=\cfrac{ x +y}{3}\)

as aforementioned

Answer 15

i agree with you jdoe0001

Answer 16

wow, you guys are amazing <3 i would give you all a medal if i could

Answer 17

thank you everyone who has spent the time to help me, your actions will not go unforgotten :)

Answer 18

your welcome xD