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Integrate 2/x√lnx
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hint: let u = ln(x), so du/dx = 1/x which means du = dx/x
also, \[\Large \sqrt{x} = x^{1/2}\]
So would the answer be 4(lnx)^1/2+c?
you are correct
that's the same as \[\Large 4\sqrt{\ln(x)} + C\]
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