please help!!!
When a point charge of (-q) is placed at corner (A) of the square shown in the figure , the magnitude of the electric field at the center of the square is found to equal 6.70 × 10-4 N/C. What is the magnitude of the electric field at the center of the square when a charge (-q) is placed at corner (A), a charge (-q) is placed at corner (B), a charge (+q) is placed at corner (C), and a charge (+q) is placed at corner (D)?

Question

please help!!!
When a point charge of (-q) is placed at corner (A) of the square shown in the figure , the magnitude of the electric field at the center of the square is found to equal 6.70 × 10-4 N/C. What is the magnitude of the electric field at the center of the square when a charge (-q) is placed at corner (A), a charge (-q) is placed at corner (B), a charge (+q) is placed at corner (C), and a charge (+q) is placed at corner (D)?

anonymous · Answer

|dw:1422933150101:dw|

shamim · Answer

Do u know the formula to calculate electric field?

shamim · Answer

Do u know hw to find out the direction of electric field?

shamim · Answer

Plz response. I wanna help u

anonymous · Answer

v=EPE/q0

shamim · Answer

Electric field
E=(1/4*pi*afcylon not)(q/r^2)

shamim · Answer

Nd direction of E is toward negative charge

shamim · Answer

Direction of E is away frm positive charge

shamim · Answer

A positive test charge will feel attraction for a negative charge n its the direction of E for that negative charge

shamim · Answer

I think u need an attachment of solution