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Chemistry 19 Online
OpenStudy (toxicsugar22):

What H30+ CONCENTRATION CORESPONDS TO THE PH VALUE 12.8

OpenStudy (toxicsugar22):

@Data_LG2

OpenStudy (anonymous):

\(\sf [H^+]= 10^{-pH}\) , where pH = 12.8 solve for [H+]

OpenStudy (toxicsugar22):

ok i got it thanks

OpenStudy (toxicsugar22):

12.8

OpenStudy (anonymous):

nope... don't get the -log of the value because you already eliminated it as I explained before.

OpenStudy (anonymous):

if you use -log(10^12.8), the value will be same as the pH, which is not true

OpenStudy (toxicsugar22):

1.584 *10^-13

OpenStudy (toxicsugar22):

right

OpenStudy (anonymous):

yes

OpenStudy (toxicsugar22):

thanks

OpenStudy (anonymous):

np :)

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