Question

What is the slope-intercept form of the function that contains the point (1, –2) and has a slope of -3
y = x +

Answer 1

HI!!

Answer 2

did you copy and paste this question without looking at it maybe?

Answer 3

no.

Answer 4

Well, the equation is y = mx + b, where m is the slope, and b is the y-intercept.

Answer 5

ooh now we see the slope

Answer 6

First we plug it into point-slope form:

\(y - y_1 = m(x - x_1)\)

Where y1 is the y-value of the point, 'm' is the slope, and x1 is the x-value of the point.

Answer 7

So in this case:

\(y_1 = -2\)
\(x_1 = 1\)
\(m = -3\)

Can you plug this into point-slope form?

\(y - y_1 = m(x - x_1)\)

Answer 8

no

Answer 9

Yes

Answer 10

We first put it in point-slope form, then we simplify to make it in slope-intercept form.

Answer 11

We distribute the slope into the parenthesis, and add/subtract 'y1' to both sides..

Answer 12

y+2=-3(x-1) ?

Answer 13

Yep, you got it.

Answer 14

yes that looks good

Answer 15

So now we distribute -3 into the parenthesis:

\(y + 2 = -3(x - 1)\)

\(y + 2 = -3x + 3\)

Now subtract 2 to both sides, what do you get?

Answer 16

-3x+1

Answer 17

Yep, so our final answer is:

\(y = -3x + 1\)