Mathematics
8 Online
OpenStudy (anonymous):
Simplify Problem:
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OpenStudy (anonymous):
\[\sqrt{2}\div \sqrt[3]{2}\]
OpenStudy (anonymous):
It is really set up like this:
OpenStudy (anonymous):
@iGreen @AnswerMyQuestions @563blackghost
OpenStudy (anonymous):
\[\sqrt{2} = 2^{1/2}\] when dividing exponents you subtract.
OpenStudy (anonymous):
Oh no it isn't
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OpenStudy (anonymous):
no thats not the answer im saying squareroot is 1/2 exponent
OpenStudy (anonymous):
Okay,
OpenStudy (anonymous):
I just don't get how to solve it when it is in the "fraction" form I guess you can call it.
OpenStudy (anonymous):
\[\sqrt[3]{2} \implies 2^{1/3}\]
OpenStudy (anonymous):
\[\large \frac{ 2^{1/2} }{ 2^{1/3} } \implies 2^{1/2-1/3}\]
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OpenStudy (anonymous):
Oh okay, that makes sense, So now what happens with the other half of the equation. I know you put \[\sqrt{2}=\sqrt{2}\frac{ 1 }{ 2 }\]
OpenStudy (anonymous):
How do I subtract two exponential fractions if they have two different denominators?
OpenStudy (anonymous):
its just fractions at this point
OpenStudy (anonymous):
OKay
OpenStudy (anonymous):
how would you normally do 1/2-1/3?
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OpenStudy (anonymous):
You would change the denominators??? So that they were the same. SO its 2 and 1/6
OpenStudy (anonymous):
\[2\frac{ 1 }{ 6 }\]
OpenStudy (anonymous):
yes 2^(1/6)
OpenStudy (anonymous):
\[2^{1/6}\]
OpenStudy (anonymous):
Thank you