Question

Question 5.5. You have 0.5 L of air at 203 K in an expandable container that allows for a constant pressure. You heat the container to 373 K. What is the volume of air?
(Points : 1)
0.27 L

0.67 L

0.92 L

2.7 L

Answer 1

@carsonsi

Answer 2

0.67 L i believe

Answer 3

\(\sf PV=nRT\)

P, R, n constant

\(\sf \cancel PV=\cancel{nR}T\rightarrow \dfrac{V}{T}=constant\)

therefore \(\sf \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\)