Question

For the principal quantum number n=3, how many possible values are there for the angular momentum quantum number (l)?

2
3
6<<< my guess
8

Answer 1

why 6? what is your reasoning behind it?

Answer 2

@aaronq nah, its what I'm going with for the moment........

Answer 3

in other words, what kinds of orbitals can you have when n=3?

s, p, d, f?

Answer 4

you have s and p orbitals, in the n=3 shell?

@aaronq

Answer 5

you can have s, p and d orbitals when n=3.

recall that \(0\leq l\leq n-1\).

thus when n=3, \(l=2, 1, 0\)

Answer 6

so 6! @aaronq

Answer 7

um nope. l = 2, 1, 0

3 values