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Mathematics 11 Online
OpenStudy (anonymous):

simplify z^5x^3/z^4x

OpenStudy (anonymous):

@jdoe0001

OpenStudy (jdoe0001):

\(\bf \cfrac{z^5x^3}{z^4x}\implies \cfrac{z\cancel{ zzzz}xx\cancel{ x}}{\cancel{ zzzz}\cancel{ x}}\)

OpenStudy (jdoe0001):

or you could do it as explained before but subtracting the exponents, would give the same

OpenStudy (anonymous):

so x^2?

OpenStudy (anonymous):

I mean zx^2

OpenStudy (jdoe0001):

well, yes but youi're mising a "z" there let us see using the negative exponents \(\bf a^{-{\color{red} n}} \implies \cfrac{1}{a^{\color{red} n}}\qquad \qquad \cfrac{1}{a^{\color{red} n}}\implies a^{-{\color{red} n}} \\ \quad \\ \\ \quad \\ \quad \\ \cfrac{z^5x^3}{{\color{brown}{ z^4x}}}\implies z^5x^3{\color{brown}{ z^{-4}x^{-1}}}\implies z^5{\color{brown}{ z^{-4}}}x^3{\color{brown}{ x^{-1}}} \\ \quad \\ z^{5-4}x^{3-1}\implies zx^2\) yeap

OpenStudy (anonymous):

write (2b)^3 without exponents fill in the blank (2b)^3 =

OpenStudy (jdoe0001):

\(\large \bf (ab)^n\implies a^nb^n\)

OpenStudy (jdoe0001):

so you pretty much just, distribute the exponent

OpenStudy (anonymous):

so 222bbb? but what about the second part? is it 8b^3?

OpenStudy (jdoe0001):

\(8b^3\) is correct

OpenStudy (anonymous):

what about the first part was that right?

OpenStudy (jdoe0001):

yes.... you could expand it to 2*2*2*b*b*b but the "simplified" version would be \(8b^3\)

OpenStudy (anonymous):

can you help me with a few more?

OpenStudy (jdoe0001):

sure, tis easier posting anew though more eyes, thus if I dunno, someone else may and we can revise each other :)

OpenStudy (anonymous):

ok :-)

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