simplify z^5x^3/z^4x
@jdoe0001
\(\bf \cfrac{z^5x^3}{z^4x}\implies \cfrac{z\cancel{ zzzz}xx\cancel{ x}}{\cancel{ zzzz}\cancel{ x}}\)
or you could do it as explained before but subtracting the exponents, would give the same
so x^2?
I mean zx^2
well, yes but youi're mising a "z" there let us see using the negative exponents \(\bf a^{-{\color{red} n}} \implies \cfrac{1}{a^{\color{red} n}}\qquad \qquad \cfrac{1}{a^{\color{red} n}}\implies a^{-{\color{red} n}} \\ \quad \\ \\ \quad \\ \quad \\ \cfrac{z^5x^3}{{\color{brown}{ z^4x}}}\implies z^5x^3{\color{brown}{ z^{-4}x^{-1}}}\implies z^5{\color{brown}{ z^{-4}}}x^3{\color{brown}{ x^{-1}}} \\ \quad \\ z^{5-4}x^{3-1}\implies zx^2\) yeap
write (2b)^3 without exponents fill in the blank (2b)^3 =
\(\large \bf (ab)^n\implies a^nb^n\)
so you pretty much just, distribute the exponent
so 222bbb? but what about the second part? is it 8b^3?
\(8b^3\) is correct
what about the first part was that right?
yes.... you could expand it to 2*2*2*b*b*b but the "simplified" version would be \(8b^3\)
can you help me with a few more?
sure, tis easier posting anew though more eyes, thus if I dunno, someone else may and we can revise each other :)
ok :-)
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