Question

State the missing element of each ordered pair so that the ordered pair belongs to the solution set of the equation.
a) x+y=9; -> (4,__), (__,1), (-3,__), (__,-5), (12,__)
b) x-y=6; -> (9,__), (__,2), (5,__), (__,-3), (-8,__)
c) 2x+y=15; -> (1,__), (__,3), (5,__), (__,-5), (7,__)

Answer 1

well, it's kind of just subtraction, for example
x+y = 9
so if x = 4 then y =5

Answer 2

ok then how about for the second one (___,1) @Jadeishere

Answer 3

Well, try it

Answer 4

I'm not so sure of how I'm supposed to subtract it

Answer 5

Is there some sort of rule to it?

Answer 6

@Jadeishere ^^^

Answer 7

Sorry, anywho, no. It's just 9- the number given and you'll get your answer

Answer 8

kk so 9-1=8 soo...(8,1) alright
what about with x-y=6

Answer 9

the same concept :)

Answer 10

Kind of! Since it is x - y = 6, it's going to be (for example) 9 - y = 6

Answer 11

Okay, I believe i understand that... and what about 2x+y=15

Answer 12

Again, i'll be using the first pair
if 2x + y = 15 then substitute the x value into the equation 2(1) + y = 15 then 3 + y = 15, subtract 3 from 15, and y = 12 :) Think you can do the rest?

Answer 13

How'd you get 3 isnt y 13

Answer 14

2x1+13=15

Answer 15

Oh oops!! Good thing you caught me /).<

Answer 16

lol

Answer 17

wait, was i right for that one? y=13

Answer 18

im so confused

Answer 19

Yeah, you're right

Answer 20

what about (___,3)

Answer 21

just plug in the value
2x + (3) = 15
2x = 12
x = 6

Answer 22

okay thank you so much

Answer 23

Of course :)