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Mathematics 16 Online
OpenStudy (anonymous):

sinx-sinx cos^2x

OpenStudy (anonymous):

@iambatman

OpenStudy (anonymous):

@chosenmatt @jdoe0001

OpenStudy (anonymous):

please help anyone!

OpenStudy (anonymous):

what help do you want with this?

OpenStudy (anonymous):

Please help me solve it, I'm having troubles with it.

OpenStudy (anonymous):

ok thats what i thought

OpenStudy (anonymous):

sinx - sinx cos2x = sin3x remember that sin2x + cos2x = 1, so cos2x = 1 - sin2x, and we can substitute that in place of cos2x... sinx - sinx (1 - sin2x) = sin3x now distribute the sinx into the parentheses... sinx - (sinx - sin3x) = sin3x sinx - sinx + sin3x = sin3x sin3x = sin3x

OpenStudy (anonymous):

This really helped, but i have one question. Why did you equal it to sin3x at the beginning?

OpenStudy (anonymous):

@Okean

OpenStudy (anonymous):

because sinx-sinxcos^2x=sinx so so its sin3x

OpenStudy (anonymous):

OHHHH ok thank you so much!!

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