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Mathematics
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sinx-sinx cos^2x
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@iambatman
@chosenmatt @jdoe0001
please help anyone!
what help do you want with this?
Please help me solve it, I'm having troubles with it.
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ok thats what i thought
sinx - sinx cos2x = sin3x remember that sin2x + cos2x = 1, so cos2x = 1 - sin2x, and we can substitute that in place of cos2x... sinx - sinx (1 - sin2x) = sin3x now distribute the sinx into the parentheses... sinx - (sinx - sin3x) = sin3x sinx - sinx + sin3x = sin3x sin3x = sin3x
This really helped, but i have one question. Why did you equal it to sin3x at the beginning?
@Okean
because sinx-sinxcos^2x=sinx so so its sin3x
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OHHHH ok thank you so much!!
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