How can Newton's second and third law both be true at the same time for a falling object? Explain.
another question: Explain how if an object has a constant speed, how is its accelaration still at zero?
1. Can you tell me which laws and interpret what you they mean. 2. Acceleration is change in velocity.
second and 3rd laws
Second law -> F=ma Third law F = - F What can we make of this?
second Law: An objects acceleration if dependent on 2 variables, its mass and net force Third Law: For every action there is an opposite reaction
because acceleration is the rate of change of velocity/speed. So if speed is constant, then acceleration=0.
How can Newton's law both be true at the same time for a falling object? Explain.
Well I answered 2 already above, and for if you have a falling object |dw:1423092112418:dw| F = ma, and the third law is being incorporated, Drag = - Weight
I believe that what is desired is that while the earth through the gravitational force is causing the object to "fall" the object itself is producing a force on the earth (albeit essentially zero), the reaction to the force of the earth on the falling object. So for every action ( force of the earth on an object) there is an equal and opposite reaction ( force of the object on the earth)
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