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Show that the reciprocal of an odd function is odd?
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an odd function is defined as f( -x ) = - f(x)
lets make a new function g(x) = 1 / f(x) , where f(x) is an odd function. is g(x) an odd function?
I tried out several examples and they all tell me that it is an odd function. But I don't understand how I can prove that algebraically.
you need to show that g(-x) = - g(x) , where g(x) = 1/f(x) , and f is an odd function
g(-x) = 1/f(-x) and -g(x) = -1/f(x) But since f(x) = f(-x) .. Ah those two are the same!
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Thanks a lot! I understand it now :3
actually f(-x) = -f(x)
g(-x) = 1 / f(-x) = 1 / (-f(x)) = - 1/f(x) = - g(x) but i figure thats what you meant
does that make sense?
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