Question

Question is in comment below

Answer 1

Find equations of the tangent lines to the curve \[y=\frac{ x-1 }{x+1 }\]
that are parallel to the line \[x-2y=2\]

Answer 2

i have been able to differentiate \[y=\frac{ x-1 }{x+1 }\] and got \[y \prime=\frac{ 2 }{ (x+1)^2 }\] i did this in an effort to get m but i am not sure what m is in this case

Answer 3

Are you able to determine the slope of\[x-2y=2\]

Answer 4

yes its 1/2

Answer 5

Great. y' is the expression for the slope of y. So, for what value(s) of x does y' = 1/2?

Answer 6

if i do \[\frac{ 1 }{ 2 }= \frac{ 2 }{(x+1)^2 }\]
i get
\[x^2+2x=1\]
and i dont know how to solve for x here

Answer 7

x^2+2x=3 sorry

Answer 8

Here's how I would tackle it:
1) multiply both sides by (x=1)^2 to get it out of the denominator, giving\[\frac{ \left( x+1 \right)^2 }{ 2 } = 2\]Then multiply both sides by two to give\[\left( x+1 \right)^2 = 4\]Are you able to solve for x?

Answer 9

yes...thank you so so much

Answer 10

Terrific. Good work.