Evaluate sin(7pi/2)
\[Sin \frac{ 7\pi }{ 2 }\]
subtract 2pi to find it on the unit circle. whenever the value isn't on the unit circle either subtract or add 2pi
hint: (7pi/2) - 2pi = (7pi/2) - (4pi/2) (7pi/2) - 2pi = (7pi-4pi)/2 (7pi/2) - 2pi = 3pi/2 that means 7pi/2 and 3pi/2 are coterminal angles which means sin(7pi/2) = sin(3pi/2)
you just need to evaluate sin(3pi/2)
^basically
so the answer is the sin(7pi/2)?
i meant sin(3pi/2)
you need to keep going and evaluate sin(3pi/2)
i don't know how...
do you have a unit circle with you?
i never learned the unit circle in precalc
i pulled one up on the computer but i don't know how to use it
strange how it's the fundamental basics in trig let's draw a blank xy axis |dw:1423019877850:dw|
draw a circle that is centered at the origin (0,0) |dw:1423019901662:dw|
this circle has a radius of 1 that's why it's called the unit circle (unit = 1)
the angle of 3pi/2 radians is equal to 270 degrees so we start at (1,0) and we rotate 270 degrees counterclockwise to land at (0,-1) |dw:1423019967074:dw|
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