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use integration by parts to evaluate the integral
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\[\int\limits_{}^{} (x^2 + 2x) \cos dx\]
I guess my u = x^2 + 2x and dv = cosx
so du = 2x + 2 and v = sinx
ok if you do that then set up the integral using the pattern forr integration by parts
if it was me, i would distribute first might not make a difference, but it would look nicer
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distribute what?
\[\int x^2\cos(x)dx+2\int x\cos(x)dx\]
oh!!! I did not even notice that thanks
\[x\cos(x)\] is real real fast, the other takes two steps
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