Question

Solve for t in lnt - ln (t^2) =5

Answer 1

how would you use e to cross off ln?

Answer 2

\[\ln(t) - \ln(t^2) \implies \ln \left( \frac{ t }{ t^2 } \right)\]

Answer 3

the answer would be t = 1/e^5 correct?

Answer 4

Yes, that seems good to me

Answer 5

okay thank you. could you help me with another one?

Answer 6

solve for x in log2x+log2(x-2)=3

Answer 7

Pretty much the same process

Answer 8

x=-4 and x=2?

Answer 9

\[\log_b(xy) \implies \log_b(x)+\log_b(y)\]

Answer 10

Idk can you show your work, and I'll see if your steps are right or not?

Answer 11

yeah one second

Answer 12

x(x+2)=2^3
x^2+2x=8
x^2+2x-8=0

Answer 13

It's x-2 i thought

Answer 14

oh your right

Answer 15

so would i just switch the negative and positive around

Answer 16

Yeah, so x = 4 is your solution

Answer 17

thank you.

Answer 18

What about 2^5x/2^x when trying to simplify?

Answer 19

Check this out, I made this a while back it's a basic tutorial on logarithm stuff, if you get stuck just ask then, give it a read: http://openstudy.com/users/iambatman#/updates/5403fdfde4b0f2ed1e14206a

Answer 20

would it be 5?

Answer 21

Not quite

Answer 22

\[\frac{ 2^{5x} }{ 2^x } \implies 2^{4x}\]

Answer 23

which is just 16^x

Answer 24

oh, is it that you just divide the one 2^x?

Answer 25

When you divide exponents you subtract, it's like when you're multiplying and you have exponents you add them, right?

Answer 26

yes