Question

medal!
write an equation of the circle with center (-2,3) and radius 9

Answer 1

Remember that the standard form of the equation of a circle is denoted by
\[(x-h)^2 + (y-k)^2 = r^2\]
where (h,k) are the coordinates of the center and r is the radius

Answer 2

so is it setup (-2 - 3)^2 + (-2 - 3)^2

Answer 3

Since you have the coordinates of the center and the radius then you'll have it as:
\[(x-(-2))^2 +(y-3)^2 = 9^2\]
Simplify

Answer 4

x2+4x+y2-6y-68

Answer 5

this that correct

Answer 6

is ths*

Answer 7

Simplifying you'll have:
\[(x+2)^2 +(y-3)^2 = 9^2\]
\[x^2 + 4x + 4 + y^2 -6y + 9 = 81\]
Simplify that further

Answer 8

you get x2+4x+y2-6y-68

Answer 9

Your answer should be an equation.
It should be
\[x^2 + 4x + y^2 - 6y - 68 = 0\]

Answer 10

Thank you! much appreciated