Please help with math
1. To open these doors, you must match the number and type of solutions for the following two functions in standard form. f(x) = x2 + 6x – 16 g(x) = x2 +6x + 1 Match the following descriptions of the solutions to each of the functions above. Hint: they each have their own match. Two real irrationals solutions Two real rationals solutions 2. To pass by me, you must tell me how to convert standard form into the general, vertex form... I have a test on it next week.” Explain how to convert f(x) into the general, vertex form of the equation. Use complete sentences.
@Hero @iambatman can y'all help please. i need this done and it looks like chinese
@hartnn pls
@gnrfan can you find the solutions for f(x)?
first of all, just by looking at f(x) you should immediately know the number of solutions there is
so can you tell how many solutions it has?
3 im guessing :/
no
ok so lets rewrite it properly, you need the ^ to show exponents ok?
yes
so you have f(x) = x^2 + 6x – 16, correct?
on the bottom it shows a bunch of ? do you mean g(x) = x^2 +6x + 1?
you may have to refresh the page, its a glitch, but yeah thats fine,
ok so can you tell me the degree of the polynomial, x^2 + 6x + 1
hold while i solve it
um ok
you dont need to solve it to know the degree
but you have to solve anyways, so might as well i guess, i was just trying to make a point
ph
well its 2
ok the degree is two, so that means it will have 2 roots aka 2 solutions, whatever the degree of the polynomial is, it will have that many roots or solutions
so if you have a polynomial of degree 5, it will have 5 solutions
k, got it
ok so that doesnt help eliminate any answers since both answers have 2 solutions, so yeah now you need to find the roots of g(x) and the roots of f(x)
and you need to determine which has rational solutions and which has irrational solutions
so can you tell me the solutions for f(x) or g(x), ?
hold on
k
what formula do I use to solve these?
you can use the quadratic formula if you like, or you can just set f(x) = 0 and isolate x on one side (which is solving for x)
i recommend you become familiar with both methods
try the second method, first set f(x) = 0
x^2 + 6x - 16 = 0
now isolate x on one side of the equation
so f(x)=x^2+6x-16=0?
yes thats valid, but get rid of the f(x)= part because we dont need it right now
since we know what f(x) = you dont need to write it, its redundant
x=-8,2
pefect, now is -8 a rational number? is 2 a rational number?
yes, i think. I kinda forgot how to tell
ok a rational number can be represented as the ratio of two integers, put it another way, a fraction in which the numerator is an integer and the denominator is an integer
you know what an integer is?
a whole number right
yes its a whole number, more specifically its a whole number that can be positive or negative or 0
ok so can we represent -8 as a ratio of two integers?
yes
yes we can, we can have -8/1, -4/2, 4/-2 8/-1,
cool
so -8 is a rational number
yes
so tell me is sqrt(5) a rational number?
do you mean the sqrt of 5 or just sqrt of 5
by the way i mean 16/-2 and -16/2 instead of 4/-2 and -4/2, sorry for the confusion lol
its rational
square root of 5 is not rational, you cannot represent it as the ratio of two integers
oh, my bad
so how about square root of 25 is that a rational number?
no, not rational
actually square root of 25 is rational, because square root of 25 is either +5 or -5, and +5 can be represented as a ratio of two integers and -5 can be represented as a ratio of two integers
wow, well at least im learning this stuff instead of just being told im wrong by a teacher
lol thats good, i hope you have better teachers in the future, either you or your parents need to talk to your teacher and the principal if necessary to discuss how you are not understanding and the teacher needs to explain it to you
yea, well whats next good sir?
thats what the teacher is paid to do, so if they arent doing their job, they need to quit or be fired
ok so now you can answer, the first question
so what is the answer that matches f(x)
Two real irrationals solutions or Two real rationals solutions
remember the solutions were -8 and 2
two real rationals
yep, so you know from the hint that that g(x) must be irrational, since the hint says each one has a match
yup
if you work out the solutions for g(x) you will see they are -3 - 2sqrt(2), and 2sqr(2) - 3
and since we know sqrt(2) is irrational, then -3 -2sqrt(2) must also be irrational, so that confirms our answer for g(x)
yea, can u help with the second part too?
so do you need help with number 2 or you good on that?
ok 1 sec, let me read it
lol
lol
ok so its asking you to write f(x) in vertex form , is that correct?
yup
but i gotta use complete sentences though. i hate that
lol
yeah its kinda annoying but not that hard
so do you know the steps to convert standard form to vertex form?
give me something in standard form and i'll convert it and see if im right
ok so lets use the problem as the example , so i have f(x) = x^2 + 6x - 16, that is currently in standard form, convert it to vertex form
y=(x+3)^2-25
perfect, what method did you use to get that answer
i don't know. I just did the way i was taught
you used completing the square right?
i think so
ok well you dont have to call it completing the square if you dont want to, but yeah you understand how to do it, now can you tell me the first step you took.
first i put it equal to y, then i did the sqr on the right side, then i re-ordered the right side to match the parabola
ok so if you were explaining it to someone trying to teach them, would that make any sense? what you just said, you need to write out sentences that would make sense to somebody just learning how to do it
pretend you are teaching someone how to do it, explain in details each step so they can understand what you mean
k hold on
Set the polynomial equal to y to find the properties of the parabola. y=x2+6x−16 Complete the square on the right-hand side of the equation. More Steps (x+3)2−25 Reorder the right-hand side of the equation to match the standard form of a parabola. y=(x+3)2−25
@billj5
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