Mathematics
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OpenStudy (anonymous):
Write in the Complex Form (a+bi)
(5+i)^2
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OpenStudy (anonymous):
@Nnesha
OpenStudy (anonymous):
@bohotness
OpenStudy (mathstudent55):
First, square the binomial.
Either use the square of a binomial formula, or use FOIL.
Then collect like terms and write it in a + bi form.
OpenStudy (mathstudent55):
Here is the formula you need.
\((a + b)^2 = a^2 + 2ab + b^2\)
OpenStudy (anonymous):
i got 25+10i+i^2 but idk how to write that in complex form
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OpenStudy (anonymous):
@mathstudent55
ganeshie8 (ganeshie8):
Hint : \[\large i^2 = -1\]
OpenStudy (anonymous):
24+10i
ganeshie8 (ganeshie8):
thats it!
OpenStudy (anonymous):
could i ask you one more question?
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ganeshie8 (ganeshie8):
sure ask
OpenStudy (anonymous):
i-6
---
i
ganeshie8 (ganeshie8):
First, divide \(i\) by each term in the numerator
OpenStudy (anonymous):
i thought you would multiply it
ganeshie8 (ganeshie8):
\[\large \dfrac{i-6}{i} = \dfrac{i}{i} - \dfrac{6}{i} = 1 - \dfrac{6}{i}\]
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ganeshie8 (ganeshie8):
you're right, now multiply \(i\) top and bottom of the second term
ganeshie8 (ganeshie8):
\[\large 1 - \dfrac{6\color{gray}{\times i}}{i\color{gray}{\times i}}\]
ganeshie8 (ganeshie8):
\[\large 1 - \dfrac{6i}{i^2}\]
ganeshie8 (ganeshie8):
\[\large 1 - \dfrac{6i}{-1}\]
ganeshie8 (ganeshie8):
\[\large 1 +6i\]
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OpenStudy (anonymous):
thank you!
ganeshie8 (ganeshie8):
just so you know you may multiply the conjugate top and bottom of the given expression directly as well..