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Mathematics 17 Online
OpenStudy (anonymous):

I have this portfolio I'm doing in geometry and it's really confusing. I have like 6 questions that I'm struggling with. it involves a wheelchair ramp. please help!

OpenStudy (anonymous):

What grade are you in?

OpenStudy (anonymous):

first I have to sketch the right triangle in this picture. would it be like this? the picture is at a bad angle sorry.

OpenStudy (loser66):

|dw:1423096436615:dw|

OpenStudy (loser66):

then, the right triangle must be

OpenStudy (loser66):

|dw:1423096605764:dw|

OpenStudy (anonymous):

ok thank you for the reassurance. can you help me with the rest?

OpenStudy (loser66):

not sure, just post. if i can, i will

OpenStudy (anonymous):

Use the Converse of the Pythagorean Theorem to verify that the measurements of your wheelchair ramp are consistent with those of a right triangle. If the measurements are not, explain why you think this might be. the measurements of the ramp are 4ft by 36inches. so \[c^2=a^2+b^2\] I'm just not sure where to go from there.

OpenStudy (loser66):

first off, 4ft = ?? inches?

OpenStudy (anonymous):

48 inches

OpenStudy (loser66):

|dw:1423097448842:dw| , so? which leg is 48, which is 36?

OpenStudy (anonymous):

the base is 48?

OpenStudy (loser66):

yup, surely the horizontal leg must be longer than the height, right?

OpenStudy (loser66):

|dw:1423097725502:dw|

OpenStudy (loser66):

apply pythagorean, can you find out c?

OpenStudy (anonymous):

\[36^2+48^2=3600\]

OpenStudy (loser66):

that is c^2, not c

OpenStudy (loser66):

|dw:1423097950867:dw|

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