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Geometry 20 Online
OpenStudy (anonymous):

write the sine, cosine, and tangent ratios for

OpenStudy (anonymous):

the base is 48in.

OpenStudy (danjs):

Which one is angle A

OpenStudy (anonymous):

the right angle?

OpenStudy (danjs):

\[\sin(A) = \frac{ opposite }{ hypotenuse }\]

OpenStudy (danjs):

I will assume angle A is the one at the base of the ramp, since you labeled the vertical side the opposite side.

OpenStudy (danjs):

You first have to calculate what the length of the hypotenuse is, using the pythagorean theorem... \[(hypotenuse)^2=36^3+48^2\]

OpenStudy (anonymous):

hypotenuse^2=46656+2304 =48960 sqrt48960 =221.3

OpenStudy (danjs):

A^2 + B^2 = C^2 I think i typed a 36^3 on accident..

OpenStudy (danjs):

\[hypotenuse = \sqrt{48^2+36^2} = 60\]

OpenStudy (anonymous):

ok I thought that was weird lol.

OpenStudy (anonymous):

ok sin(A)= 36/60?

OpenStudy (anonymous):

@DanJS

OpenStudy (danjs):

yes

OpenStudy (anonymous):

wait ok I'm not sure how to do that @DanJS

OpenStudy (anonymous):

@Directrix can you help me?

Directrix (directrix):

What did you get for the hypotenuse?

OpenStudy (anonymous):

60

Directrix (directrix):

|dw:1423103694789:dw|

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