f'(x)=e^-x^2 f(5)=1 Find f(2). Thanks!
does this say \[f(x)=e^{-\frac{x^2}{2}}\]??
integrate, and based on f(5)=1 find C. then find f(2)
are you sure that is the derivative ?
positive
then f(5)\(\large\color{slate}{\displaystyle\ne}\)1
how do you integrate with the e? and the end of your post is coming out in code... not sure what its supposed to be
if that is the derivative, \(\large\color{slate}{f'(x)=e^{-\frac{x^2}{2}}}\). then you can use the error function, or maybe a power series.......
you will not find a simple result. (I don't think so)
If it was something like \(\large\color{slate}{f'(x)=xe^{-\frac{x^2}{2}}}\) that would be much neasier.
*easier.
What is the (large/color(slate) thing?
oh, you don't see any cool math symbols, just some random codes?
yup
that is then a latex-processing error.
I will draw what I said.|dw:1423103592877:dw|
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