Question

I kind of get this side of the worksheet; I tried to figure it out, but it was just not getting to me in a good way. Please help and fan and medal will be rewarded! :D

Answer 1

reupload as a pdf please

Answer 2

thanks

Answer 3

do you have anything done for this at all?

Answer 4

you're welcome, probably #3 I can do since it seems straight forward, but #'s 1 & # 2 are very confusing to me.

Answer 5

To be honest, #1's graph or image seems really hard to see. I'm not sure what's going on there.

Answer 6

for #2, you can graph that out to help you get started

I'd use something like desmos

https://www.desmos.com/calculator

Answer 7

#3 I graphed it on a graphing calculator, and it looks like it shift down 18 units: https://www.desmos.com/calculator

Answer 8

can you not see graph on problem #1

Answer 9

you should have this graph for #2

Answer 10

no I can't

Answer 11

Scroll all the way to the bottom for the pdf that I posted, so it can give you a clear look for the problem:
http://www.slcschools.org/departments/curriculum/math/documents/6.4aquadratictransformations.pdf

Answer 12

ok I can see it a bit better, but I'm still having trouble picking out the pigs (I'm guessing this is supposed to be angry birds or something)

Answer 13

is the pig in the very back?

Answer 14

the pigs are located Quadrant 4 and the birds are located in Quadrant 3

Answer 15

yes the graph is based off of the games Angry Birds

Answer 16

ok I think I have this right. I put the starting point in a red box and the pig in a green oval. Let me know what you think

Answer 17

yes that's fantastic! :D

Answer 18

so you have to draw a parabola through them both

Answer 19

is it like a full on out parabola or a half of one

Answer 20

I think a full one

Answer 21

which bird should I use or am I using that boxed in area

Answer 22

that I'm not sure since I haven't played the game

I guess the one I boxed in?

Answer 23

oh wait, there is more than one bird in the box

Answer 24

hmm idk

Answer 25

let's do (-8, -3)

Answer 26

let's do (-7.5, -3) so the parabola can reach the point (9, -1)

Answer 27

alright, tell me what you get

Answer 28

Well I calculated the midpoint between (-7.5,-3) and (9, -1) to get (3/4, -2)

Answer 29

ok that works, that'll be your third point

Answer 30

slope is 4/33

Answer 31

this is a parabola, so slope won't apply here

Answer 32

figuring this out is hard for me

Answer 33

do you have geogebra?

Answer 34

Algebra 3 (III)

Answer 35

no i mean the computer program geogebra

Answer 36

it's a graphing tool

Answer 37

no I have a graphing calculator

Answer 38

can you install new programs onto your computer?

for me, geogebra is the best tool to find the parabola we need

Answer 39

actually, you don't need to install anything if you don't want to

you can use the web based version

Answer 40

yea I can install it if it can get my worksheet done lol

Answer 41

anyways, go here

https://www.geogebra.org/

Answer 42

@jim_thompson5910 What do I do?

Answer 43

do you have the program running now?

Answer 44

yes

Answer 45

ok go ahead and plot the three points

Answer 46

you can type in each point at the bottom

Answer 47

where do I put it

Answer 48

do you see the input bar at the bottom?

Answer 49

its toward the top

Answer 50

what do I put in the input bar

Answer 51

each point one at a time

Answer 52

now what

Answer 53

those points are labeled A, B, and C right?

Answer 54

yep

Answer 55

ok now you'll type in

FitPoly[{A,B,C},2]

the "{A,B,C}" are the list of points you want the polynomial to go through
the '2' means we want a second degree polynomial

Answer 56

it gave me a function

Answer 57

and you should see the graph of that function too, right?

Answer 58

f(x) = 0.12 * x - 2.09

Answer 59

I don't know if that's what I am suppose to get, but it is what it is

Answer 60

it should be a quadratic

Answer 61

can you post a screenshot of your geogebra window?

Answer 62

let me try again

Answer 63

Nope it's the same one

Answer 64

you're not able to post a screenshot?

Answer 65

no I am on the computer, but I exactly type in what you had and that's what it gave me

Answer 66

ok try this, move the midpoint up a few units and see what happens

Answer 67

the midpoint (3/4,-2) doesn't make a parabola but a straight line

Answer 68

the midpoint is now (0.29,-3.35)

Answer 69

well I think if you move that midpoint up, then it should make a parabola

it won't be a midpoint anymore but in a way, it's in the middle

Answer 70

is my point good

Answer 71

I'd move it up though, not down, but I guess either way is fine

Answer 72

as long as you have the bird following the parabola to hit the pig, then you pretty much have it

Answer 73

@jim_thompson5910 what's the domain and range of -0.13x^2 + 0.31x + 6.5? When we right domain or range sometimes it's like this: [0, positive infinity), but this is what Wolfram Alpha said: Is it right? http://www.wolframalpha.com/input/i=domain+and+range+of+-0.13x%5E2+%2B+0.31x+%2B+6.5

Answer 74

the wolfram link you gave me doesn't work

Answer 75

try again

Answer 76

click the link and you'll see what I mean

Answer 77

http://www.wolframalpha.com/input/?i=domain+and+range+of+-0.13x%5E2+%2B+0.31x+%2B+6.5

Answer 78

yeah wolfram is correct

Answer 79

although, the range does look a bit funky

Answer 80

but if I was doing like we've done in class I would I say it

Answer 81

oh I see now

Answer 82

you need to solve for y in

5200y <= 34761

Answer 83

y = 6.68

Answer 84

yeah so the largest y value is roughly 6.68

Answer 85

that's where the parabola peaks out

Answer 86

for part C on number 1 I said its wider than normal

Answer 87

yes it is

Answer 88

what about for #2, how do I answer A, B, and C?

Answer 89

you can use geogebra to graph that function they give you

Answer 90

before you do, make sure you're done with #1

Answer 91

because it's best to clear everything and start over

Answer 92

#1 is done because I wrote the equation and I wrote down the domain and range of the equation

Answer 93

for the last part is to compare my function to y = x^2

Answer 94

ok then #2