Question

I need help with graphing these linear equations:
2x+3y=-12
2x-y=-4

Answer 1

if x = 0 for 2x+3y=-12, then what is the value of y?

Answer 2

2(0)+3y=-12

Answer 3

that 2(0) turns into 0

when you add 0 to 3y, it stays as 3y

Answer 4

so we have 3y = -12

Answer 5

3y=-12
3 divided by 3 =1
-12 divided by 3 = -4

Answer 6

now what do i have to do

Answer 7

@jim_thompson5910 ^^

Answer 8

yes, so if 3y = -12, then y = -4

Answer 9

together we have x = 0 and y = -4

Answer 10

so the point (0,-4) lies on 2x+3y=-12

Answer 11

now solve for x when y = 0

Answer 12

2x+3(0)=-12

Answer 13

2x=-12

Answer 14

2 divided by 2 is 1 and -12 divided by 2 is -6

Answer 15

yep, so we know that (-6,0) lies on the line 2x+3y=-12

Answer 16

the two points (0,-4) and (-6,0) lie on 2x+3y=-12

Answer 17

you just need 2 points to construct a straight line

Answer 18

(0,-4) is the y-intercept
(-6,0) is the x-intercept

Answer 19

Alright how about for the second one

Answer 20

you'll do the same as we did for the first equation

Answer 21

I'll let you try it out for practice

Answer 22

okay so y-int x=0
2(0)-y=-4
-1y=-4
-1y divided by -1 is 1. -4 divided by -1 is 4
y=4
(0,4)

Answer 23

am i right?

Answer 24

(0,4) is on 2x-y=-4, correct

Answer 25

x-int y=0
2x-0=-4
2x=-4
2 divided by 2 is 1. -4 divided by 2 is -2
x=-2
(-2,0)

Answer 26

very good, you have the correct points

Answer 27

@jim_thompson5910 thanks for the help!

Answer 28

you're welcome