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whats the integral of cosx?
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\[\int\limits_{?}^{?} cosx dx\]
-sin(x) + C If you ever don't know the antiderivative of a trigonometric function, you can always think of it like "What function is -cos(x) the derivative of?" I know that the derivative of sin(x) is cos(x), so the antiderivative is just the opposite.
what happens to the cosx?
u= cosx and dx=-du/sinx
\[\int\limits_{?}^{?} u (-du/sinx)\]
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is that right?
batman?
@iambatman you there? i just want some proof of how integral of cosx is -sinx+c
We just use \[\frac{ d }{ dx } cosx = -sinx\]
There's not much to the proof, \[\int\limits sinx dx = -cosx+C\]
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so i just put that as my answer and dont show any work
No need to
okay
Recall we are using the fundamental theorem of calculus
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