Question

does anyone know how this would be solved?
e^xe^(x+1)=1

Answer 1

e^(1.609) = 4.998
(positive because it was -x and the answer was negative)

regardless, to solve an equation like this you need to know inverse operations:
the inverse operation for e is ln (natural log), because ln(e^x) = x and e^ln(x) = x

therefore, you would solve the equation by taking the ln of both sides

ln(e^-x) = ln(4)
therefore, -x = ln(4) = 1.386, so x = -1.386

that would be the answer unless i am misunderstanding the syntax of the math problem.
Hope this helped! :)

Answer 2

start by using the exponents rule a^x * a^x = a^2x

Answer 3

\[e ^{xe ^{x+1}}=1\]

Answer 4

its e^(x) e^(x+1)=1 so not with the exponent having another exponent added to it sorry i dont know how to write it correctly :P

Answer 5

yeah I worked it out. just start with what I wrote before

Answer 6

does that mean that its like this
e^x * e^(x+1) = e^2x+1
e^2x+1 =1

Answer 7

yes, that's it. now for the rest we can see that e^0 =1
so e^(2x+1) = e^0

what do you think we do next?

Answer 8

2X+1=0
2X=-1
X=-1/2

Answer 9

very good! you're getting the hang of this

Answer 10

thanks :D

Answer 11

no problem

Answer 12

with all of these if you want to check the answer just substitute the final x value into the original equation

Answer 13

ok cool thank you!!!