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Mathematics 13 Online
OpenStudy (anonymous):

Please help! i will medal and fan!

OpenStudy (anonymous):

OpenStudy (anonymous):

@MARC_

OpenStudy (anonymous):

Im so conufused i alpologize

OpenStudy (anonymous):

there are two points \[(\frac{ 1 }{ 2 },2)\] and \[(-3,-1)\]

OpenStudy (anonymous):

Given that there are two equation \[-6x+7y=11\] and \[-7x+6y=-11\]

OpenStudy (anonymous):

Now try substitute \[x=\frac{ 1 }{ 2 }\] into the equation

OpenStudy (anonymous):

Right so i would choose B or A?

OpenStudy (anonymous):

\[-6(\frac{ 1 }{ 2 })+7y=11\]\[-7(\frac{ 1 }{ 2 })+6y=-11\]

OpenStudy (anonymous):

u have to try both in order to get the correct one

OpenStudy (anonymous):

if u get \[y=2\],that equation is the correct standard form.

OpenStudy (anonymous):

if u don't want to use the first point\[(\frac{ 1 }{ 2 },2)\],u can use the second point\[(-3,-1)\]

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