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@MARC_
Im so conufused i alpologize
there are two points \[(\frac{ 1 }{ 2 },2)\] and \[(-3,-1)\]
Given that there are two equation \[-6x+7y=11\] and \[-7x+6y=-11\]
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Now try substitute \[x=\frac{ 1 }{ 2 }\] into the equation
Right so i would choose B or A?
\[-6(\frac{ 1 }{ 2 })+7y=11\]\[-7(\frac{ 1 }{ 2 })+6y=-11\]
u have to try both in order to get the correct one
if u get \[y=2\],that equation is the correct standard form.
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if u don't want to use the first point\[(\frac{ 1 }{ 2 },2)\],u can use the second point\[(-3,-1)\]
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