Question

help

Answer 1

\[\frac{ y(x+y) }{ y(x-y) }=\frac{ x+y }{x-y }\]

Answer 2

What are you trying to figure out exactly?

Answer 3

both are equal if you add the condition \(y \ne 0\)

Answer 4

what do you mean?

Answer 5

i have just guessed, whats ur question exactly ? :)

Answer 6

i know that they are equal.

Answer 7

but my question is what would it be like if you distributed the Y in the first expression.

Answer 8

The same.

Answer 9

interesting, yeah we can disttribue.. nobody gona stop us from doing that. so ?

Answer 10

\[\frac{ y(x+y) }{ y(x-y) }=\frac{ yx+y^2) }{ yx-y^2) }\]

Answer 11

would it be this?

Answer 12

tRUE

Answer 13

Looks good

Answer 14

They are equal

Answer 15

\[\frac{ y^2 }{ y^2 } = ?\]

Answer 16

1

Answer 17

how does that work?

Answer 18

\[\dfrac{a+b}{c+d} \ne \dfrac{a}{c} + \dfrac{b}{d}\]

Answer 19

3/3 = 1
assume y is a number y /y = 1

Answer 20

you are trying to distrbute y of something to y of things then each will take one

Answer 21

ahhh i understand now.

Answer 22

but isn't it like this

Answer 23

a/c+d + b/c+D = a+b/c+D

Answer 24

3/3 why 1 ? each one will take one

Answer 25

\[\frac{ y^2 }{ y^2 } = y^0\]

Answer 26

y^0 = 1

Answer 27

ohhh i get it now!! omg i love you all thank you all <3<3

Answer 28

yw